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         Fundamental Theorem Of Algebra:     more books (18)
  1. The Fundamental Theorem of Algebra (Undergraduate Texts in Mathematics) by Benjamin Fine, Gerhard Rosenberger, 1997-06-20
  2. Constructive aspects of the fundamental theorem of algebra. Proceedings of a symposium conducted at the IBM Research Laboratory by Bruno, Henrici, Peter, Editors Dejon, 1969
  3. Constructive aspects of the fundamental theorem of algebra;: Proceedings of a symposium conducted at the IBM Research Laboratory, Zurich-Ruschlikon, Switzerland, June 5-7, 1967,
  4. Constructive aspects of the fundamental theorem of algebra. Proceedings of a symposium conducted at the IBM Research Laboratory by Bruno, Henrici, Peter, Editors Dejon, 1969-01-01
  5. Abstract Algebra: Vector Space, Group, Linear Map, Polynomial, Euclidean Vector, Cauchy Sequence, Fundamental Theorem of Algebra, Power Set
  6. Fundamental Theorems: Fundamental Theorem of Algebra, Fundamental Theorem of Arithmetic, Finitely Generated Abelian Group
  7. Field Theory: Field, P-Adic Number, Fundamental Theorem of Algebra, Hyperreal Number, Galois Theory, Finite Field, Algebraically Closed Field
  8. Fundamental Theorem of Algebra
  9. Imaginary Unit: Real number, Complex number, Iota, Polynomial, Imaginary number, Root of unity, Algebraic closure, Complex plane, Fundamental theorem of algebra
  10. Constructive Aspects of the Fundamental Theorem of Algebra by Bruno & Peter Henrici. Eds. Dejon, 1969
  11. Complex Analysis: Euler's Formula, Complex Number, Euler's Identity, Exponential Function, Polynomial, Fundamental Theorem of Algebra
  12. Constructive Aspects of the Fundamental Theorem of Algebra by Bruno and Peter Henrici. Eds. Dejon, 1969
  13. Constructive aspects of the fundamental theorem of algebra. Proceedings ofa symposium conducted at the IBM Research Laboratory by Bruno, Henrici, Peter, Editors Dejon, 1969-01-01
  14. Algebraic Analysis: Solutions and Exercises, Illustrating the Fundamental Theorems and the Most Important Processes of Pure Algebra by George Albert Wentworth, James Alexander McLellan, et all 2010-01-11

41. Math If Being Spammed With Clours Is Your Idea Of A Good Client, See Bitch X Bet
schnitzl, tehdod do you mean this http//en.wikipedia. org/wiki/fundamental_theorem_of_algebra ? action, sniper89 just got his coffee and is now going to
http://ircarchive.info/math/2007/4/17/58.html
#math - Tue 17 Apr 2007 between 18:12 and 18:24
Page: Prev Next Last Day: Previous Next
nawa if being spammed with clours is your idea of a good client, see bitch x better - looks neater and/or is easier to use and/or has better functionality
:D delewis nawa: those are easy to disable. lillpelle sniper89: this is offtopic delewis sniper89: I recommend 'telnet' right, sorry
lol
yeah, and some fackin' diddy donuts!
well.
gotta concentrate on maths action sniper89 needs caffeine needs caffeine tehdod is there any proof that each equtation on n'th degree has n solutions? delta I'm not clear what you mean exactly. schnitzl tehdod: do you mean this: http://en.wikipedia.org/wiki/Fundamental_theorem_of_algebra action sniper89 just got his coffee and is now going to start doing his homework just got his coffee and is now going to start doing his homework
I know you don't care anyway :P tehdod true/
that one. tehdod x^2 = is a 2th equation and has only 1 solution... no ? delewis there's a proof for it.
there are still two solutions. tehdod StaZ[home]: not true
anyway i know theres topological one delewis the proof that I've seen for the FTA involves a bit of Galois theory.

42. Why Do We Use Complex Numbers
http//en.wikipedia.org/wiki/fundamental_theorem_of_algebra By this way, roots F(x)=0 maybe Complex. In the other side Laplace transform is like a
http://www.edaboard.com/ftopic173414.html
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Author Message serimc

Joined: 07 Jan 2005
Posts: 18
31 May 2006 16:05 Why do we use complex numbers Hi
s=a+jb
2 dimensional expreesion.Why do we need to use this?In laplace transform or fourier ,we all transfer our mathematical expreesion to 2 dimensional domain.Right?
But why do we do this?What is the magic behind the curtains?In engineering we do everything with transforms.I do also.But still i don't know what a complex number is.
Can you explain what comlex numbers indicate please?
I hope i can expalin what i mean.
I am looking for your answers Back to top anomaly Joined: 09 May 2006 Posts: 19 Helped: 31 May 2006 17:28 Why do we use complex numbers This may help some: http://mathforum.org/library/drmath/view/53809.html Back to top DMan Joined: 20 Oct 2005 Posts: 40 Helped: Location: Slovenia 31 May 2006 17:44 Re: Why do we use complex numbers If you apply nonperiodic signal to the electronic system your response will be nonperiodic and therefore you should observe it in time domian. If you apply periodic signal to the system and you observe the response in time domain you will see that the response repeats it self-is periodic with the period of the input signal Therefore you are interested only in observing signal in the time in one period. the next period is a copy of past etc.

43. Fundamental Theorem Of Algebra DBpedia.org
Translate this page http//dbpedia.org/resource/fundamental_theorem_of_algebra . http//www4.wiwiss.fu-berlin.de/flickrwrappr/photos/fundamental_theorem_of_algebra
http://dbpedia.org/resource/Fundamental_theorem_of_algebra

44. When Are Two Proofs Essentially The Same? « Gowers’s Weblog
http//en.wikipedia.org/wiki/fundamental_theorem_of_algebra Proofs I consider the proofs listed in the wikipedia article under complex analysis and topology
http://gowers.wordpress.com/2007/10/04/when-are-two-proofs-essentially-the-same/
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Mathematics related discussions The exchange lemma and Gaussian elimination A paper on the ArXiV
When are two proofs essentially the same?
A general remark that becomes clear quickly when one thinks about this is that there are fairly standard methods for converting one proof into another, and when we apply such a method then we tend to regard the two proofs as not interestingly different. For example, it is often possible to convert a standard inductive proof into a proof by contradiction that starts with the assumption that is a minimal counterexample. In fact, to set the ball rolling, let me give an example of this kind: the proof that every number can be factorized into primes. The usual approach is the minimal-counterexample one: if there is a positive integer that cannot be factorized, let be a minimal one;

45. Fundamental Theorem Of Algebra
Shop for fundamental_theorem_of_algebra at mlshopping.com .. page is retrieved from http//en.wikipedia.org/wiki/fundamental_theorem_of_algebra under GFDL.
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Fundamental theorem of algebra
In mathematics , the fundamental theorem of algebra states that every complex polynomial p z in one variable and of degree n has some complex root . In other words, the field of complex numbers is algebraically closed and therefore, as for any other algebraically closed field, the equation p z has n roots ( not necessarily distinct). The name of the theorem is now considered something of a misnomer by many mathematicians, since it is not fundamental for contemporary algebra
Contents
  • History Proofs
    History
    Peter Rothe (Petrus Roth), in his book Arithmetica Philosophica (published in 1608), wrote that a polynomial equation of degree n (with real coefficients) may have n solutions. Albert Girard , in his book L'invention nouvelle en l'Alg¨bre (published in 1629), asserted that a polynomial equation of degree n has n . However, when he explains in detail what he means, it is clear that he actually believes that his assertion is always true; for instance, he shows that the equation x x , although incomplete, has four solutions: i , and i As will be mentioned again below, it follows from the fundamental theorem of algebra that every polynomial with real coefficients and degree greater than

46. Fundamental Theorem Of Algebra - Biocrawler
fundamental_theorem_of_algebra. Retrieved from http//www.biocrawler. com/encyclopedia/fundamental_theorem_of_algebra
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Fundamental theorem of algebra
From Biocrawler
In mathematics , the fundamental theorem of algebra states that every complex polynomial of degree n has exactly n zeroes , counted with multiplicity. More formally, if (where the coefficients a a n can be real or complex numbers), then there exist ( not necessarily distinct) complex numbers z z n such that This shows that the field of complex numbers , unlike the field of real numbers , is algebraically closed n a and the sum of all the roots equals - a n The theorem had been conjectured in the 17th century but could not be proved since the complex numbers had not yet been firmly grounded. The first rigorous proof was given by Carl Friedrich Gauss in 1799. (An almost complete proof had been given earlier by d'Alembert .) Gauss produced several different proofs throughout his lifetime. All proofs of the fundamental theorem necessarily involve some analysis , or more precisely, the concept of continuity of real or complex polynomials. The main difficulty in the proof is to show that every non-constant polynomial has at least one zero. We mention approaches via complex analysis topology , and algebra
  • Find a closed disk D of radius r p z p z r p z D is therefore achieved at some point z in the interior of D p z m p z ) is a holomorphic function in the entire complex plane. Applying

47. 代数学の基本定理
Translate this page Category deFundamentalsatz_der_Algebraenfundamental_theorem_of_algebra esTeorema_fundamental_del_álgebrafrThéorème_de_d Alembert-Gaussko _
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fundamental theorem of algebra x n n x f x f x c c x f x c Category:代数学 de:Fundamentalsatz_der_Algebra en:Fundamental_theorem_of_algebra es:Teorema_fundamental_del_¡lgebra fr:Th©or¨me_de_d'Alembert-Gauss ko:대수학의_기본_정리 nl:Hoofdstelling_van_de_Algebra pl:Zasadnicze_twierdzenie_algebry sl:Osnovni_izrek_algebre sv:Algebrans_fundamentalsats zh:代数基本定理
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48. Fundamental Theorem Of Algebra - Definition Of Fundamental Theorem Of Algebra -
This article is licensed under the GNU Free Documentation License. It uses material from the Wikipedia article fundamental_theorem_of_algebra . Browse
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The fundamental theorem of algebra (now considered something of a misnomer by many mathematicians) states that every complex polynomial of degree n has exactly n zeroes, counted with multiplicity. More formally, if (where the coefficients a a n can be real or complex numbers), then there exist ( not necessarily distinct) complex numbers z z n such that This shows that the field of complex numbers , unlike the field of real numbers , is algebraically closed n a and the sum of all the roots equals - a n The theorem had been conjectured in the 17th century but could not be proved since the complex numbers had not yet been firmly grounded. The first rigorous proof was given by Carl Friedrich Gauss in 1799. (An almost complete proof had been given earlier by d'Alembert .) Gauss produced several different proofs throughout his lifetime. All proofs of the fundamental theorem necessarily involve some analysis , or more precisely, the concept of continuity of real or complex polynomials. The main difficulty in the proof is to show that every non-constant polynomial has at least one zero. We mention approaches via complex analysis topology , and algebra
  • Find a closed disk D of radius r p z p z r p z D is therefore achieved at some point z in the interior of D p z m p z ) is a holomorphic function in the entire complex plane. Applying

49. Fundamental Theorem Of Algebra - Exampleproblems
Retrieved from http//exampleproblems.com/wiki/index. php/fundamental_theorem_of_algebra . Categories Abstract algebra Complex analysis Field theory
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Fundamental theorem of algebra
From Exampleproblems
Jump to: navigation search In mathematics , the fundamental theorem of algebra states that every complex polynomial of degree n has exactly n roots (zeros), counted with multiplicity . More formally, if (where the coefficients can be real or complex numbers), then there exist ( not necessarily distinct) complex numbers such that This shows that the field of complex numbers , unlike the field of real numbers , is algebraically closed . An easy consequence is that the product of all the roots equals n a and the sum of all the roots equals a n A weaker form of this theorem had been conjectured in the 17th century by Albert Girard. In his book (published in 1629), he asserted that every polynomial equation of degree n with real coefficients has n solutions, but he did not state that they were necessarily complex numbers. A first attempt at proving the theorem was made by d'Alembert in 1746, but his proof was incomplete. Other attemps were made by Euler Lagrange (1772), and Laplace (1795). These last three attemps assumed implicitely Girard's assertion; to be more precise, the existence of solutions was assumed and all that remained to be proved was that their form was a b i for some real numbers a and b A much more rigorous proof (which did not assume the existence of roots) was published by Gauss in 1799, but it had a topological gap. A rigorous proof was published by

50. PROOT Taking Too Loooooong ... [HP48]
http//nostalgia.wikipedia.org/wiki/fundamental_theorem_of_algebra http//education.ti.com/educationportal/sites/US/productDetail/us_polyroot_89.html
http://www.adras.com/PROOT-taking-too-loooooong.t1420-182.html
in [ Prev: Is there a Capital Pi function in the 50g?
Next: Even Mathematica wont solve this.
From: Peter A. Gebhardt on 20 Sep 2006 16:14 Below are the coefficients of an Internal Rate of Return (IRR) problem:
] PROOT
The above cashflows result into a (period-based) return of 1.164062 %
per period (periods are supposed to be months) = 13.968748 % per year.
Both my HP17BI+ and my TI BAII Plus Professional give correct answers
in about 2 seconds using their standard (built-in) cash-flow routines..
My HP49G+ (2.09) is still running and trying to solve after 2 minutes
What is the problem here?
Best regards, Peter A. Gebhardt From: John H Meyers on 20 Sep 2006 16:36 On Wed, 20 Sep 2006 16:14:40 -0500, Peter A. Gebhardt wrote: Besides that you should *reverse* the flows before using PROOT to solve for IRR, what's going on is that PROOT finds *all* roots (100 of them in this case :) and that these are all computed over the *complex*plane* is that sufficient explanation? Try taking your *original* (not reversed) matrix (best entered in "Approximate" mode, because "integer" objects slow things down)

51. Title
http//www.clarku.edu/~djoyce/complex http//en.wikipedia.org/wiki/fundamental_theorem_of_algebra
http://gifted.cet.ac.il/gifted/skira/numbers/numbers8.asp dir=rtl

52. Fundamental_theorem_of_algebra - SpivO Encyclopedia - Find Your
fundamental_theorem_of_algebra SpivO Encyclopedia - Find Your Channel
http://spivo.com/encyclopedia/?title=Fundamental_theorem_of_algebra

53. 0387946578: "Fundamental Theorem Of Algebra" By Benjamin Fine And Gerhard Rosenb
Find the best deals on Fundamental Theorem of Algebra by Benjamin Fine and Gerhard Rosenberger (0387946578)
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54. Fundamental Theorem Of Algebra
McFLY. Title page. Fundamental theorem of algebra. The fundamental theorem of algebra (now considered something of a misnomer by many mathematicians) states
http://en.mcfly.org/Fundamental_theorem_of_algebra
Warning /wikipedia/lang.php on line
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55. Polynom N-ten Grades Nur N Nullstellen
Translate this page http//en.wikipedia.org/wiki/fundamental_theorem_of_algebra. Thomas. Auf deutsch http//www.matheboard.de/lexikon/index.p atz_der_Algebra
http://www.matheboard.de/archive/4135/thread.html
Polynom n-ten Grades nur n Nullstellen
SirJective
Nun die interessante Frage - wie folgt daraus, dass es nur n Nullstellen haben kann, wenn ich nur n Linearfaktoren abspalten kann?
Gruss,
SirJective Gnu Ben Sisko Zitat: Original von SirJective
Nun die interessante Frage - wie folgt daraus, dass es nur n Nullstellen haben kann, wenn ich nur n Linearfaktoren abspalten kann?
Ist das nicht einfach: "Ein Produkt ist Null, wenn mindestens eins seiner Faktoren Null ist." Also die Nullteilerfreiheit?!?
@Gnu: Nullstellenberechnung wird zwar in der Schule meistens in der Analysis im Rahmen einer Kurvendiskussion behandelt, aber an sich gehört es in die Algebra. Der Hauptsatz der Algebra, den du ansprichst, besagt, dass man im Körper der komplexen Zahlen jedes Polynom in n Linearfaktoren aufspalten kann (wenn n sein Grad ist). In C kann man also "...hat höchstens n Nullstellen." ersetzen durch "...hat genau n Nullstellen."
SirJective
Gibst du uns noch ein Beispiel eines Polynoms, das mehr Nullstellen hat als sein Grad angibt? Ben Sisko Heute jedenfalls nicht mehr genau Irrlicht
Die Aussage, dass jedes nichtkonstante komplexe Polynom mindestens eine Nullstelle hat, ist der sogenannte "Fundamentalsatz der Algebra". Sein Beweis erfordert Hilfsmittel der Analysis. Ich kenne 3 Beweise aus der Funktionentheorie. Hier sind noch ein paar:

56. Fundamental Theorem Of Algebra - Wikipedia
Fundamental theorem of algebra. Redirected from Fundamental Theorem of Algebra. The fundamental theorem of algebra (now considered something of a misnomer
http://wikipedia.inetbridge.net/fu/Fundamental_Theorem_of_Algebra.html
Wikipedia Wiki Content
Fundamental theorem of algebra
[Your user agent does not support frames or is currently configured not to display frames. However, you may visit the related document. The fundamental theorem of algebra (now considered something of a misnomer by many mathematicians) states that every complex polynomial of degree n has exactly n zeroes, counted with multiplicity. More formally, if (where the coefficients a a n can be real or complex numbers), then there exist (not necessarily distinct) complex numbers z z n such that This shows that the field of complex numbers , unlike the field of real numbers , is algebraically closed . An easy consequence is that the product of all the roots equals (-1) n a and the sum of all the roots equals - a n The theorem had been conjectured in the 17th century but could not be proved since the complex numbers had not yet been firmly grounded. The first rigorous proof was given by Carl Friedrich Gauss in the early 19th century. (An almost complete proof had been given earlier by d'Alembert .) Gauss produced several different proofs throughout his lifetime. It is possible to prove the theorem by using only algebraic methods, but nowadays the proof based on

57. Fundamental Theorem Of Algebra
Fnd. The Fundamental Theorem of Algebra states that every complex polynomial of degree. n has exactly n zeroes, counted with multiplicity. More
http://september-1.wikipedias.co.uk/uk/Fundamental_Theorem_of_Algebra
Fundamental Theorem of Algebra
Fnd The Fundamental Theorem of Algebra states that every complex polynomial of degree n has exactly n zeroes, counted with multiplicity. More formally, if
p z z n a n z n-1 a
(where the coefficients a a n can be real or complex numbers), then there exist (not necessarily distinct) complex numbers z z n such that
p z z z z z z z n

This shows that the field of complex numbers is, unlike the field of real numbers , an algebraically closed field . An easy consequence is that the product of all the roots equals (-1) n a and the sum of all the roots equals - a n
The theorem had been conjectured in the 17th century but could not be proved since the complex numbers had not yet been firmly grounded. The first rigourous proof was given by Carl Friedrich Gauss in the early 19th century. Gauss produced several different proofs throughout his lifetime. It is possible to prove the theorem by using only algebraic methods, but nowadays the proof based on complex analysis seems most natural. The difficult step in the proof is to show that every non-constant polynomial has at least one zero. This can be done by employing

58. Top40-Charts.com - 40 Top 20 & Top 40 Music Charts From 25 Countries
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59. Vieta-Formel - Newsgroup Archive
Translate this page http//en.wikipedia.org/wiki/fundamental_theorem_of_algebra. Ich hatte an den AFAIK von Weil gebrachten Beweis gedacht
http://www9.newsgroup-archive.com/t_5514322059478143118_s_Vieta-Formel.html
Home
Vieta-Formel
From: Subject: Vieta-Formel Date: $$DATE$$ Die Vieta-Formel dient bekanntlich dazu, kubische
Gleichungen im casus irreducibilis ohne Umweg ins
Komplexe l=F6sen zu k=F6nnen. Das funktioniert modulo
Tippfehler wie folgt: Man startet mit der Gleichung
x^3 + a_1 x^2 + a_2 x + a_3 =3D
und substituiert dann x =3D y - a_1 / 3, was auf
y^3 =3D 3 Q y - 2 R
mit
Q =3D (a_1^2 -3 a_2) / 9
und
R =3D (2 a_1^3 - 9 a_1 a_2 + 27 a_3) / 54. f=FChrt. Sodann liefert der Ansatz y =3D - 2 sqrt(Q) c die Gleichung 4 c^3 - 3 c =3D R / Q^(3/2), die man mit dem Ansatz c =3D cos phi und einem Additionstheorem l=F6sen kann. Zwei Fragen dazu: Gr=FC=DFe, Bettina From: Subject: Re: Vieta-Formel Date: $$DATE$$ Vielen Dank, diese Sachen sind mir jetzt klar. Als n=E4chstes benutzt man c =3D cos phi und 4 c^3 - 3 c =3D cos(3 phi). Damit soll angeblich phi =3D 1 / 3 (arccos(R / Q^(3/2)) + m pi) mit m =3D 0,2,4 folgen. Wie kommt man auf m =3D 2 und 4? From: Subject: Re: Vieta-Formel Date: $$DATE$$ "Bekanntlich"? streng monoton wachsend, hat also nur eine einfache reelle Nullstelle. Ergo: Kein casus irreducibiles.

60. Brak Pliku.
Brak pliku.
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