61. Fundamental Theorem Of Algebra Contents. Fundamental theorem of algebra. Redirected from Fundamental Theorem of Algebra. The fundamental theorem of algebra (now considered something of a http://www.ebroadcast.com.au/lookup/encyclopedia/fu/Fundamental_Theorem_of_Algeb

Make eBroadcast my Homepage Contact Us It's Web Guide Encyclopedia Contents Fundamental theorem of algebra Redirected from Fundamental Theorem of Algebra The fundamental theorem of algebra (now considered something of a misnomer by many mathematicians) states that every complex polynomial of degree n has exactly n zeroes, counted with multiplicity. More formally, if (where the coefficients a a n can be real or complex numbers), then there exist (not necessarily distinct) complex numbers z z n such that This shows that the field of complex numbers , unlike the field of real numbers , is algebraically closed . An easy consequence is that the product of all the roots equals (-1) n a and the sum of all the roots equals - a n The theorem had been conjectured in the 17th century but could not be proved since the complex numbers had not yet been firmly grounded. The first rigorous proof was given by Carl Friedrich Gauss in the early 19th century. (An almost complete proof had been given earlier by d'Alembert .) Gauss produced several different proofs throughout his lifetime. It is possible to prove the theorem by using only algebraic methods, but nowadays the proof based on complex analysis seems most natural. The difficult step in the proof is to show that every non-constant polynomial has at least one zero. This can be done by employing

62. Website Hosting Translate this page Fundamental theorem of algebra Teorema fundamental da álgebra. In mathematics , the fundamental theorem of algebra states that every non-zero http://pt.webarcheo.com/Fundamental_theorem_of_algebra

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Cebirin Temel Teoremi Poll without page-refresh Create your own web poll Article on other languages: Teorema_fonamental_de_l' lgebra Z¡kladn­_věta_algebry Algebraens_fundamentals¦tning Teorema_fundamental_del_¡lgebra ... Add to OnlyWire şeklindeki karmaşık katsayılı bir polinomunun k¶kleri, p x polinomu i§ersinde x bilinmeyeni yerine konduğunda sonucu veren değerlerdir. Cebirin Temel Teoremi sabit olmayan (yani derecesi en az bir olan) kompleks katsayılı her p x polinomu i§in en az bir kompleks k¶k olduğunu ifade eder. Matematik ile ilgili bu madde bir taslaktır . Ä°§eriğini geliştirerek Vikipedi'ye katkıda bulunabilirsiniz http://tr.wikipedia.org/wiki/Cebirin_Temel_Teoremi "'dan alındı Sayfa kategorileri Matematik taslakları Cebir Teoremler This article is from Wikipedia . All text is available under the terms of the GNU Free Documentation License

66. Fundamental Theorem Of Algebra Definition | Define Fundamental Theorem Of Algebr Fundamental Theorem Of Algebra meaning including Fundamental Theorem Of Algebra definition and what Fundamental Theorem Of Algebra actually means! http://www.math-glossary.info/definition/1007-Fundamental_Theorem_Of_Algebra

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67. Re: Spincronic Shows His Stupidity - Again. http//en.wikipedia.org/wiki/fundamental_theorem_of_algebra. Ya, you should try to read it. You can have real complex coefficients, with 2 solutions for http://newsgroups.derkeiler.com/Archive/Talk/talk.origins/2007-10/msg01144.html

Re: Spincronic shows his stupidity - again. From Date : Wed, 03 Oct 2007 13:21:33 -0700 On Sun, 30 Sep 2007 11:30:27 -0700, the following appeared in talk.origins, posted by spintronic spintronic wrote: Sure you did! O.k, we will walk you back to your room now, everything will be o.k. Watch the step! sure sounds like a jealous drunk trollslob Jealous of what? some lying old guys delusions? I dont think so! Let him be, he will be dead soon. Then we can all have a rest! You however need to rethink your GR. You wouldn't know anything about GR. You have trouble with freshman algebra, as shown by your "10 solutions to a second-degree equation" howler. 8, solutions. Non of which you can prove wrong! Spin: The fundamental theorem of algebra: Every polynomial equation (rational coefficients) of degree 'n' has exactly 'n' roots. For more: http://en.wikipedia.org/wiki/Fundamental_theorem_of_algebra Ya, you should try to read it. aX^2 - aX = 0, where a is the coefficient. Uh.. that isn't "an equation", that's four different equations. Uh...

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Category:Fundamental theorem of algebra From Wikimedia Commons, the free media repository Jump to: navigation search Media in category "Fundamental theorem of algebra" This category contains only the following file. Tfa.svg 15,426 bytes Retrieved from " http://commons.wikimedia.org/wiki/Category:Fundamental_theorem_of_algebra Categories Polynomials Mathematical theorems Views Category Discussion Edit History Personal tools Log in / create account Navigation Main Page Welcome Community portal Village pump Participate Upload file Recent changes Latest files Random file ... Donate Search Toolbox What links here Related changes Upload file Special pages ... Permanent link This page was last modified on 12 November 2007, at 00:03. Text is available under GNU Free Documentation License Wikimedia® is a registered trademark of the Wikimedia Foundation, Inc. About Wikimedia Commons

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<= k <= n, I have to determine a maximum > weighted bipartite matching with a cardinality of k. It's obvious, > that for k = n we have the well-studied maximum weighted bipartite > matching problem (and it can be solved in polynomial time). But is > there already an polynomial-time algorithm to solve the problem if k > is smaller than n? I've no idea, and what about you? Sascha You can easily reduce the weighted bipartite maximum matching problem where k < n to a complete bipartite case by introducing additional nodes and edges of weight zero. The Hungarian method (Kuhn,1955) solves the assignment problem in O(n^3) time. Such is the point of view espoused in Chapter 11 (Weighted Matching) of: Combinatorial Optimization - Algorithms and Complexity Papadimitriou and Steiglitz (Dover, 1998) === Subject: Re: Variation of the Maximum Weighted Bipartite Matching Problem > You can easily reduce the weighted bipartite maximum > matching problem where k < n to a complete bipartite case all edges can have arbitrary non-negative weights. So this method can't be applied. === Subject: Re: Variation of the Maximum Weighted Bipartite Matching Problem > You can easily reduce the weighted bipartite maximum > matching problem where k < n to a complete bipartite case all edges can have arbitrary non-negative weights. So this method > can't be applied. I don't see your point. If your K_k,n bipartite graph has arbitrary non-negative weights, it can be extended to (k

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